16x^2-57x+46=0

Solution for 16x^2-57x+46=0 equation:

16x^2-57x+46=0

a = 16; b = -57; c = +46;
Δ = b2-4ac
Δ = -572-4·16·46
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{305}}{2*16}=\frac{57-\sqrt{305}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{305}}{2*16}=\frac{57+\sqrt{305}}{32}
$